这个题判断一个数是否为数,不过输入样例太扯。。。或许是自己太水,我的定义和样例的定义不一样,改了好久,难怪这个题的AC率这么低。
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class Solution {
public:
bool isNumber(const char *s) {
string str = "";
int len = strlen(s);
int i = 0;
for(;i < len;i++) {
if(s[i] == ' ')continue;
else break;
}
for(;i < len;i++) {
str.push_back(s[i]);
}
for(int i = str.length()-1;i >= 0;i--) {
if(str[i] == ' ') {
str.erase(i);
}
else
break;
}
return isNumberString(str);
}
private:
bool isNumberString(string s) {
//是否有正负号
//是否带小数点
//是否含e
//是否有前置0
int len = s.length();
if(len <= 0)return false;
if(len == 1) {
if(s[0] < '0' || s[0] > '9')return false;
else return true;
}
int start = 0;
if(s[0] == '+' || s[0] == '-') {
start = 1;
}
bool isZeroAllowed = true;
bool isPotAllowed = false;
bool isEallowed = false;
bool once = true;
if(s[start] == '.') {
if(len >= start + 2) {
if(s[start + 1] >= '0' && s[start + 1] <= '9') {
isZeroAllowed = true;
isPotAllowed = false;
isEallowed = true;
once = false;
start = start + 2;
}
else
return false;
}
else
return false;
}
for(int i = start;i < len;i++) {
if(s[i] == '.' && isPotAllowed == false) {
return false;
}
if(s[i] == '.' && isPotAllowed == true) {
isPotAllowed = false;
continue;
}
if(s[i] == 'e' && isEallowed == false) {
return false;
}
if(s[i] == 'e' && isEallowed == true) {
isEallowed = false;
isPotAllowed = false;
once = false;
if(i + 1 >= len)return false;
if(s[i+1] == '-' || s[i+1] == '+') {
if(i+2 >= len)return false;
if(s[i+2] < '0' || s[i+2] > '9')return false;
i+=2;
continue;
}
if(s[i+1] < '0' || s[i+1] > '9')return false;
continue;
}
if(s[i] >= '0' && s[i] <= '9') {
if(once == true) {
isZeroAllowed = true;
isPotAllowed = true;
isEallowed = true;
once = false;
}
continue;
}
return false;
}
return true;
}
};
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