因为形成了环,遍历每个点为起始点,并排除相邻点,假设起始点必选。借用House Robber的解法即可。
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class Solution {
public:
int robOne(vector& nums) {
if (nums.size() == 0) {
return 0;
}
vector v(nums.size() + 1);
v[0] = 0;
v[1] = nums[0];
for (int i = 1; i < nums.size(); i++) {
int j = i + 1;
if (nums[i] + v[j - 2] > v[j - 1]) {
v[j] = nums[i] + v[j - 2];
} else {
v[j] = v[j - 1];
}
}
return v[nums.size()];
}
int rob(vector& nums) {
vector numsc;
int size = nums.size();
int sum = 0;
for (int i = 0; i < size; i++) {
numsc.clear();
int tmp = nums[i];
for (int j = i; j < size; j++) {
if (j == ((i-1) < 0 ? i - 1 + size : i - 1) ||
j == ((i+1) >= size ? i + 1 - size : i + 1) ||
j == i) {
numsc.push_back(0);
continue;
}
numsc.push_back(nums[j]);
}
for (int j = 0; j < i; j++) {
if (j == ((i-1) < 0 ? i - 1 + size : i - 1) ||
j == ((i+1) >= size ? i + 1 - size : i + 1) ||
j == i) {
numsc.push_back(0);
continue;
}
numsc.push_back(nums[j]);
}
tmp += robOne(numsc);
if (tmp >= sum) {
sum = tmp;
}
}
return sum;
}
};
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